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2x^2+15x-30=23
We move all terms to the left:
2x^2+15x-30-(23)=0
We add all the numbers together, and all the variables
2x^2+15x-53=0
a = 2; b = 15; c = -53;
Δ = b2-4ac
Δ = 152-4·2·(-53)
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{649}}{2*2}=\frac{-15-\sqrt{649}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{649}}{2*2}=\frac{-15+\sqrt{649}}{4} $
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